Web(a) It is an isosceles triangle. (b) It is an obtuse triangle. (c) It is a scalene triangle. (d) It is a right triangle. (e) It is an acute triangle. 28. If point A is located at (3,1) and point B is located at (7 ; 3), which of the following for point C would make 4 ABC isosceles? (a) (0 ; 1) (b) (6 ;3) (c) ( 1; 1) (d) (3 ; 6) (e) ( 1; 3) WebPh-1,2,3 & Binomial(WA)(F) - Free download as PDF File (.pdf), Text File (.txt) or read online for free. Question bank on Compound angles, Trigonometric eqn and ineqn, Solutions of Triangle & Binomial There are 142 questions in this question bank. Select the correct alternative : (Only one is correct) Q.1 If x + y = 3 – cos4θ and x – y = 4 sin2θ then (A) x4 + …
Practice Exam 1 for Math 104.odt - Practice Exam #1: Math...
WebFor ABC shown above, ∠CAD is the exterior angle for ∠A and ∠B and ∠C are the two remote interior angles. We know that ∠CAB + ∠B + ∠C = 180°. Also, ∠CAB and ∠CAD form a straight angle, so ∠CAB + ∠CAD = 180°. Since both sums equal 180°: ∠CAB + ∠CAD = ∠CAB + ∠B + ∠C ∠CAD = ∠B + ∠C The same can be shown for any exterior angle of any triangle. WebIf ABC is an acute angle triangle, then the minimum value of tanA+tanB+tanC is A 2√2 B 3√2 C 3√3 D 2√3 Solution The correct option is B 3√3 In a ABC, we know that … the private clinic company info
If in a triangle ABC, $\\tan A+\\tan B+ \\tan C=6$ and $\\tan …
WebSolution: Since 75º = 45º+30º, place a 30−60−90 right triangle ADB with legs of length 3 and 1 on top of the hypotenuse of a 45−45−90 right triangle ABC whose hypotenuse has length 3, as in the figure on the right. From Figure 9 we know that the length of each leg of ABC is the length of the hypotenuse divided by 2. So AC = BC = 3 2 = 3 2 . WebIn an acute angled triangle ABC, if tan (A + B − C) = 1 and, sec (B + C − A) = 2, find the value of A, B and C. WebIf angle C of a triangle ABC be obtuse, then prove that tanAtanB<1. Medium Solution Verified by Toppr Since A+B=π−C, we have tan(A+B)=tan(π−C) or 1−tanAtanBtanA+tanB =−tanC>0, .(1) [∵ C is obtuse angle implies tanC<0] But since A and B are each less than π/2, it follows that tanA+tanB>0 Hence (1) will hold if 1−tanAtanB>0 or tanAtanB<1 as required. the private chow kit